The volume of a cone with base radius r and height h is:
V = 1/3 * pi * r^2 *h
This gives that the curved surface has surface area:
Area = pi * (h^2 + r^2) * [2 * pi * r] / [2 * pi * sqrt(h^2 +r^2)]
= pi * sqrt (h^2 + r^2) *r
The area of the bottom circle is of course pi * r^2 so the total
surface area of the cone is:
Area = pi * r * [sqrt (h^2 + r^2) + r]
I hope this helps you ^ is to the power and pi = 3.14159
:)
2006-10-24 06:08:28
·
answer #1
·
answered by Aqua 4
·
0⤊
0⤋
Cone Volume Theorem
The volume V of any cone with radius r and height h is equal to one-third the product of the height and the area of the base.
Formula: V = (1/3)(PI)r2h
Cone Area Theorem
The total area T of a cone with radius r and slant height l is equal to the area of the base plus PI times the product of the radius and the slant height.
Formula: T = (PI)rl + (PI)r2
2006-10-24 06:08:22
·
answer #2
·
answered by Nuthouse 4456 5
·
0⤊
1⤋
Total surface area of a cone is pie*r(r+l),where pie=22/7,r=radisu of base and l=the slant height of the cone. Volume of a cone is1/3*pie *r^2h,where pie=22/7,r=radius of the base and h=vertical height of the cone
2006-10-24 06:24:49
·
answer #3
·
answered by alpha 7
·
0⤊
1⤋
Volume of a cone = 1/3* pi * (radius)^2 * height
(Total) Surface area ofa cone = pi r l + pi r^
= pi r(l + r)
where r is radius, pi = 22/7 (approx.), l is slant height and h is height
2006-10-24 06:10:56
·
answer #4
·
answered by sushobhan 6
·
0⤊
1⤋
V = hB/3
height*Base/3
Area = pi * r * [sqrt (h^2 + r^2) + r]
2006-10-24 06:07:37
·
answer #5
·
answered by Dentata 5
·
0⤊
1⤋