An organization wants to sell tickets to a concert. It plans on selling 300 reserved tickets and 150tickets at the door. If it wants to collect at least $3750, what is the minimum price it can charge for a reserved-seat ticket?
2006-10-24 03:38:26 · 3 answers · asked by primo026 1 in Science & Mathematics ➔ Mathematics
the price of a reserved ticket is $3 more than a ticket at the door
2006-10-24 03:52:34 · update #1
You need to tell us the amount of the standard tickets.
If R = price of reserved tickets and S = price of standard tickets, then you have:
300R + 150S > 3750
Solving for R you have:
300R > 3750 - 150S
R >= (3750 - 150S)/300
R >= 12.5 - S/2
That's the best you can do without specifying the standard ticket price. So if the standard ticket price was $5, you'd have to set the reserve ticket price at $10 (at least). Or if the standard ticket price was $6, the reserve ticket price would be at least $9.50.
2006-10-24 03:43:08 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
R is reserved ticket price
D is door ticket price
R = D + 3
300R + 150D >= 3750
300(D+3) + 150D >= 3750
300D + 900 + 150 D >= 3750
450D >= 2850
D >= 2850/450 = 6.33
R >= 9.33
2006-10-24 04:05:52 · answer #2 · answered by Dr. J. 6 · 0⤊ 0⤋
lets say the tickets at the door = x
and reserved tickets is 3+x
300(3+x) + 150x = 3750
900+300x + 150x = 3750
450x = 2850
x (at the door tickets) = 6.3333 or 6.34
means at the door it would have to be 9.34 or more
2006-10-24 04:06:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋