Have 2 containers same size filled with equal amounts of gas X. One container is rigid the other is flexible. What will happen if each containers is placed in an oven 400 degrees Fahrenheit for 10 min.
2006-10-24 02:56:42 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The rigid container would stay the same size because it is rigid and can't change size. The pressure of the gas inside it would go up.
The flexible container would increase in size until the pressure of the gas inside and the pressure from the sides of the container were equal.
2006-10-24 03:00:20 · answer #1 · answered by DanE 7 · 0⤊ 0⤋
According to Gas Ideal Law :
(PV/T)1 = (PV/T)2
increasing of temperature will give place to an increasing of Volume and Pressure.
The rigid container will increase the internal pressure while volume is constant.
The flexible container will increase its volume but pressure could be maintained constant.
2006-10-24 10:01:42 · answer #2 · answered by CHESSLARUS 7 · 0⤊ 1⤋
first container pressure increases, second container, volume and pressure both.
1st case volume is constant,
so P1 / T1 = P2/T2
2nd case volume can chane
PV=nRT
2006-10-24 10:12:53 · answer #3 · answered by The Potter Boy 3 · 0⤊ 0⤋