Physics question below?

Question

A car travels at a constant speed around a circular track whose radius is 2.6 km. The car goes once around the track in 350 s. What is the magnitude of the centripetal acceleration of the car?

Answer 1

The formula for finding centripetal FORCE (not be confused with centripetal ACCELERATION) is

Fc = mv^2/r

A piece of data is missing: the mass of the car.

You can use information given above to calculate the speed by finding the circumference of the circle and dividing that by the time. Make sure your answer is in m/s. Use kg for mass and m for radius. Your answer will the be in N.

After answering the above, I re-read your question only to find that you were really asking about centripetal acceleration. O.K. This is easier.

ac = v^2/r

Firstly, find the velocity:

Using 2.pi.r, you get 2 x 22/7 x 2 600 m. Divide that by 250 s, to get the velocity, in m/s.

Square that and divide by 2 600 to get your answer in m/s^2.

You should get 1.6 m/s^2 (correct to 2 significant figures).

Please do the actual working to verify and justify the above answer. You need to SHOW how you arrive at an answer. I know. I've been a high school physics teacher for more tha 10 years. So, I made a mistake in reading your question the first time. Why did I not remove that part of the answer? Simple. After finding centripetal acceleration, the next thing you will have to learn is to find centripetal force. This way, you wouldn't have to come back with that question!!

Answer 2

the respond is B. till now the collision, you're traveling in a at present line, with the automobile pushing you forward. throughout the time of the turn, your physique tries to maintain its forward momentum, yet you're contacted by way of the automobile door via fact the automobile moved interior the direction of the turn. The door (collision) then exerts a leftward rigidity on you, inflicting you to flow in that direction with the automobile. that's called centripetal rigidity.

Answer 3

46.7