. Perform the indicated operations:
2√[48] + √[27] – 5√[12
2006-10-23 18:28:29 · 4 answers · asked by Tiffany B 1 in Science & Mathematics ➔ Mathematics
Try to simplify each term first, that might help:
2√[48] + √[27] – 5√[12] =
2√[16*3] + √[9*3] – 5√[4*3] =
2*4√[3] + 3√[3] – 5*2√[3] =
8√[3] + 3√[3] – 10√[3] =
(8 + 3 - 10)√[3] =
√[3]
2006-10-23 18:32:38 · answer #1 · answered by I ♥ AUG 6 · 0⤊ 0⤋
2â[48] + â[27] – 5â[12
2â[4*4*3] + â[9*3] – 5â[4*3
2*2*2â[3] + 3â[3] – 5*2â[3
8â[3] + 3â[3] – 10â[3
2006-10-24 01:34:19 · answer #2 · answered by Crellos 2 · 0⤊ 0⤋
2/48+/27-5/12(hey i have used slash instead of root, sorry)
=2/16*3+/9*3-5/4*3
=2*4/3+3/3-5*2/3(as 16,9and 4 are squares,we take thier square roots and take them out)
=8/3+3/3-10/3
=/3(8+3-10)...taking /3 common
=1/3
=/3
sorry again for taking slash as root
2006-10-24 01:39:22 · answer #3 · answered by Anonymous · 0⤊ 0⤋
That's cute that you got the little sqrt symbols, but can't simplify the problem
Start by prime factoring all dividends. 27 = 3^3, 12 = 3*2^2
2006-10-24 01:32:57 · answer #4 · answered by arbiter007 6 · 0⤊ 0⤋