i am a number, a multiple of 11, not odd but even, my digits (a pair) when muliplied make a cube and a square?

Answer 1

I'll suggest a simple way.
There are a pair of digits, the number is even and a multiple of 11.
There are 4 such numbers,
22, 44, 66 and 88.
Basically each number multiplied by itself makes a square number. So they all satisfy the final condition.
But only 88 satisfies all conditions as 8x8 = 64
64 is a square of 8 and a cube of 4.
therefore your number is 88.

Answer 2

Two equal digits when multiplied must make a square anyway, so that tells us nothing. If the digits multiplied make a cube, then each digit must be a cube. The only single-digit cubes are 1 and 8. The conditions of the problem disallow 1, therefore the answer is 88.

Answer 3

There aren't many possibilities.

22, 44, 66, 88

Multiply the digits in each pair and they will all be squares.

4, 16, 36, 64

So which one is a cube.... 64 since it is 4 cubed.

So the answer is 88.


Aloha

Answer 4

88

Answer 5

88

Answer 6

88 8x8=64 whose square root is 8 and cube root is 4