How much water does a 6'6" person weighing 302lbs displace in a lake of salt water?

Question

Assuming the lake is roughly heart-shaped and measures 250miles from left to right, 150miles from top to bottom, and is about 230ft deep.

Answer 1

We don't know the person's density. Assuming his density is close to the density of water, we take 302 pounds, divide by 8.33 pounds per gallon of water, that gives a volume of 36.2 gallons.

If we want cubic feet, take 36.2 gallons and divide by 7.48 gallons per cubic foot, we get about 4.85 cubic feet.

Generally, a man would have slightly greater density than water. However, the more body fat he has, the less is his density.

Answer 2

I think you can assume that anybody who weighs 302 pounds will float. Call 302 pounds of water about 5 cubic feet. As far as I know, "Heart shaped" doesn't mean anything specific in geometry. Depth doesn't matter.
Call it a 150 million square foot lake. That would be 5 cubic feet spread over 150 million sq ft or 1/30,000,000 of a foot. Convert that however you want.

Answer 3

we need to know his volume! so either get 2000 different measurements on the guy and find an estimate, or... find his density and use density and wieght to find volume.... then he will obviously displace his volume.. but... based on just the info you gave it is impossible to know.. unless your supposed to make assumptions about density ect. and the size of the lake or the fact that its salt water make no difference... if this was homework i think it might be a trick question... or at least trick in that your supposed to ignore the salt and lake size and shape. think about it man! why would the shape or size of the lake matter? the only thing that matters is the guys volume... thats it.

Answer 4

he must displace at least 302 pounds worth or he would sink like a rock. It has nothing to do with the size of the lake, just the size of that big guy.