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2006-10-23 15:19:24 · 8 answers · asked by Somebody 2 in Science & Mathematics Mathematics

8 answers

y= 2x-4 and y=2x-6

pick points for x for each equation and solve for y then graph

2006-10-23 15:23:57 · answer #1 · answered by Up_In_Smoke 2 · 0 1

Look at the two equations.

2x-y=4
2x-y=6

You'll notice, they both have the same 2x term and -y term but they are different on right side of the equation. This *should* tell you something.

Now, re-write the equation as follows
2x-y=4 ---> y=2x - 4
2x-y=6 ---> y=2x - 6
You know how to do this, correct?

Now notice, y=2x is the same. This is the slope of the graph. -4 and -6 are different. Those are Y intercepts where graph meets with tye Y axis.

Now, graph each.
For the first graph, plot a point at x= 0, y=-4. This is -4 part of the equation. From this point, go to the right 1 and up 2. That's 2X. Now, draw a line that connects both points and extends to both right and left.

For the second graph, plot a point at x=0, y=-6. Then move to right 1 and up 2. Draw a line again.

If you are dealing with systems of equations where you are trying to find values of X and Y where both equations will be true, then what you are looking for is where those lines cross.

Do they cross? No, correct?

That means your solution is "no solution."

(yes - "no solution" is really a valid answer)

p.s. If you have another problem where both lines are exactly the same, then your answre becomes the formula itself. Which is entirely different from the type of problems you asked here.

2006-10-23 15:36:21 · answer #2 · answered by tkquestion 7 · 0 0

1. Isolate y in BOTH equations.

2. Graph each equation on the SAME xy-plane.

3. The solution of the question will be where the two graphs meet.

Guido

2006-10-23 15:24:14 · answer #3 · answered by Anonymous · 0 0

2x - y = 4
2x - y = 6

Multiply top by -1

-2x + y = -1
2x - y = 6

0x = 5
x = (5/0)
x = Undefined

Since these problems have the same slope but different y-intercepts, these problems have no solution

for a graph, go to www.quickmath.com

2006-10-23 16:04:49 · answer #4 · answered by Sherman81 6 · 0 0

y=mx+b,in general form,
y=2x-4,
y=2x-6,
m=2 for both lines, so they are parallel,they differ in b. b=-4,b=-6.
There is no intersection between these two lines.
Therefore there is no solution.

2006-10-23 15:37:19 · answer #5 · answered by chanljkk 7 · 0 0

so graph both lines and find out where they intersect

y=2x-4
and
y= 2x -6
so
2x-4= 2x -6
which cannot happen since 4is not equal to 6
so there is no solution

2006-10-23 15:24:15 · answer #6 · answered by Anonymous · 0 0

Plot the two and find the coordinates of the point of intersection.
For a discussion pls IM me

2006-10-23 15:24:23 · answer #7 · answered by Anonymous · 0 1

the lines are paralle as the equations justdiffer by a constant
so no solution

2006-10-23 15:23:58 · answer #8 · answered by raj 7 · 0 2

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