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explain how to do this please! i know its easy I just cant remember.

2006-10-23 15:06:59 · 14 answers · asked by jose u 1 in Science & Mathematics Mathematics

14 answers

5^x=100
talke ln
ln(5^x)=ln(100)
xln(5)=ln(100)
x=ln(100)/ln(5)

2006-10-23 15:07:29 · answer #1 · answered by Anonymous · 1 0

Try the definition of logarithm. That number x such that when you raise 5 to it, you get 100, is defined to be:

log(5) 100,

the base-5 logarithm of 100. That's your answer, log(5) 100.

2006-10-23 22:25:45 · answer #2 · answered by alnitaka 4 · 0 0

Try log 5^x = log 100
x log 5 = log 100
Use your calculator to give you the answer.

2006-10-23 22:33:01 · answer #3 · answered by dark&pure? 3 · 0 1

5^x = 100
log(5)100 = x

x = log(5)100

if you want an approximation, then

x = (log(100))/(log(5))
x = about 2.8614

2006-10-23 23:11:39 · answer #4 · answered by Sherman81 6 · 0 0

The easiest way to solve problems like this is to set up a logorithm like others have here.

2006-10-23 22:10:42 · answer #5 · answered by Anonymous · 0 0

Is that supposed to mean 5 times x = 100?

Kay then....

5^x=100
divide 100 by 5, because that is the inverse operation of multiplication. So you get 20.

x=20

Am I right?

2006-10-23 22:09:49 · answer #6 · answered by Anonymous · 0 4

For this question, use logarithms.

5^x = 100

Taking lg on both sides, we have,

lg (5^x) = lg 100
xlg 5 = lg 100
x = (lg 100) / (lg 5)
x = 2.86

Hope this helps.

2006-10-23 22:15:54 · answer #7 · answered by xxmizuraxx 2 · 0 0

use common log instead...its easier.

log 5^x =log100
x log 5= 2
x= 2/log 5
x=2.86

2006-10-23 22:09:49 · answer #8 · answered by Kitty 2 · 1 1

x=log(100)/log(5)

2006-10-23 22:09:09 · answer #9 · answered by Ivan 5 · 0 0

xlog5=log100
xlog5=2
x=2/log5
approx. = 2.861353
Check: 5^2.862= 100.104

2006-10-23 22:11:21 · answer #10 · answered by Anonymous · 0 1

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