single rathional expression-Am I correct?

Question

(5a^2w) / (2bc^3) - (3y) / (10a^2c)

is this like simplifying?
I have this:

(25a^4w-3bc^2y) / (10bc^3a^2)

Is this correct?

Answer 1

Well Schnitzel you are pretty correct .

(5a^2w) / (2bc^3) - (3y) / (10a^2c)

• Part 1
First we need to find common denominator and it is 10 a^2 b c^3
so you did right .

• Part 2
A) 10 a^2 b c^3 / 2bc^3 = 5 a^2
(5 a^2) * (5a^2w) = 25 a^4 w
let 25 a^4 w = N1

B) 10 a^2 b c^3 / 10a^2c = b c ^2
(b c ^2) * ( 3y) = 3 b ^2 y
let 3 b ^2 y = N2

• Part 3
(N1 - N2) / common denominator
(25 a^4 w - 3 b ^2 y) / 10 a^2 b c^3

Good Job Dear ..
Good Luck .

Answer 2

(5a^2w) / (2bc^3) - (3y) / (10a^2c)

You have the right LCD: 10a^2bc^3

[5a^2(5a^2w)]/[5a^2(2bc^3)] - [bc^2(3y)]/[bc^2(10a^2c)]

[25 a^4w - 3b^2y]/10a^2bc^3

I get the same as you

Answer 3

((5a^2w)/(2bc^3)) - ((3y)/(10a^2c))

Multiply everything by 10a^2bc^3

(((5a^2)(5a^2w)) - ((bc^2)(3y)))/(10a^2bc^3)

(25a^4w - 3ybc^2)/(10a^2bc^3)

You are 100% correct

Answer 4

Yes, that is correct.