((x+2)/2x) - ((2-x)/x^2)?

Answer 1

Simplify the expression

((x+2)/2x) - ((2-x)/x^2)

(x+2)/2x - (2-x)/x^2

Multiply the left fraction by x/x and the right fraction by 2/2

[x(x + 2)]/2x^2 - [2(2 - x]/2x^2

Combine the fractions

{x(x + 2) - 2(2 - x)}/2x^2

Apply distributive rule and collect like terms in the numerator

{x^2 + 2x - 4 + 2x}/2x^2
{x^2 + 4x - 4}/2x^2

Answer 2

Find the least common demonator. (2x and x^2) then multiply x^2(x+2) - 2x(2-x) = x^3+2x^2-4x+2x^2 / 2x-x^2 then collect lik terms and that will get your answer.

Answer 3

= -x(x^2 + 10x + 8) you do the rest.. since it was to the third power there must be three answers.. obviously one is -x=0 factor out the inside and set to 0 to get the others. what i did was make
((2-x)/x^2) into ((2-x)^2)/ x^2 foiled out the top... and then cross multiplied the bottom of each with the top of the other to get rid of the fractions... combined the like terms... and pulled out an x

Answer 4

((x + 2)/(2x)) - ((2 - x)/(x^2))
((x + 2)/(2x)) - ((-x + 2)/(x^2))
((x + 2)/(2x)) - (-(x - 2)/(x^2))
((x + 2)/(2x)) + ((x - 2)/(x^2))

Multiply everything by 2x^2

(x(x + 2) + 2(x - 2))/(2x^2)

(x^2 + 2x + 2x - 4)/(2x^2)

(x^2 + 4x - 4)/(2x^2)

Answer 5

I can explain using a whiteboard takes too much time to type. IM me

Answer 6

how do we kno wat x is unless that is equal in the middle