I'm thinking of a number. When I double my number, subtract five, and then add my original number, I get one. What's my number?
2006-10-23 14:37:45 · 17 answers · asked by :) 2 in Science & Mathematics ➔ Mathematics
(2x - 5) + x = 1
(2x + x) - 5 = 1 (Associative property =P)
3x - 5 = 1
3x - 5 + 5 = 1 + 5 (Adding 5 to both sides)
-5 + 5 + 3x = 1 + 5 (Commutative Property)
3x = 6
3x/3 = 6/3 (Dividing Both Sides By 3)
x = 2 (Voila)
2006-10-23 15:08:50 · answer #1 · answered by Derek Ikawa 2 · 0⤊ 0⤋
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2006-10-23 14:58:21 · answer #2 · answered by MA A 3 · 0⤊ 0⤋
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2006-10-23 14:46:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2006-10-23 14:41:52 · answer #4 · answered by Quant 2 · 1⤊ 0⤋
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2006-10-23 14:40:58 · answer #5 · answered by Anonymous · 1⤊ 0⤋
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2006-10-23 14:40:29 · answer #6 · answered by CJ 2 · 1⤊ 0⤋
Let's take the number you thought of as 'x'.
2x-5+x = 1
3x-5 = 1
3x = 6
x = 6/3 = 2
Checking the solution:
2(2) - 5 + 2 = 4-5+2
= 6-5
= 1
2006-10-23 14:53:38 · answer #7 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
Your number is x.
2x -5 +x = 1
3x = 6
x = 2
Check: 2(2) -5 +2 = 4 -5 +2 = 1!
2006-10-23 14:40:48 · answer #8 · answered by Doctor Why 7 · 0⤊ 1⤋
2 is the number. You double get 4 subtact 5 get -1, add original 2 end in one.
2006-10-23 14:44:36 · answer #9 · answered by seec49655 1 · 0⤊ 0⤋
2x-5+x=1
3x-5=1
3x=6
x=2
2006-10-23 14:45:04 · answer #10 · answered by aw_dw4ever 2 · 0⤊ 0⤋