What is that slope equation that is something like this: rise over run...?
2006-10-23 14:26:40 · 8 answers · asked by Me 2 in Science & Mathematics ➔ Mathematics
change in y over change in x
(y2-y1)/(x2-x1)
2006-10-23 14:28:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If you are given two points (x1, y1) and (x2,y2), the equation to find the slope (m) is:
slope = m = (y2-y1) / (x2-x1)
It can be simplified as "rise (y-coordinates) over run (x-coordinates)
2006-10-23 21:37:44 · answer #2 · answered by Jabba H 1 · 0⤊ 0⤋
(x1,y1) and (x2,y2)
m = (y2 - y1)/(x2 - x1)
(x1,y1) is the first coordinate
(x2,y2) is the second coordinate
rise as you know goes up or down, so that would be the y-axis as in the difference of the y-values, and run goes left or right, so that would be the x-axis as in the difference of the x-values.
2006-10-23 23:35:41 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
it is: y2-y1 over (divided by) x2-x1
2006-10-23 21:35:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
rise/run=distance/time(squared)
2006-10-23 21:52:35 · answer #5 · answered by DeadBunnyTM 2 · 0⤊ 1⤋
y=mx+b
2006-10-23 21:49:15 · answer #6 · answered by aw_dw4ever 2 · 0⤊ 1⤋
y=mx+b
2006-10-23 21:30:17 · answer #7 · answered by Anonymous · 0⤊ 1⤋
delta y / delta x
2006-10-23 21:31:13 · answer #8 · answered by Anonymous · 0⤊ 0⤋