2. Explain how to solve ax+b=0 for x.
B. Check these solutions to equations by substituting the numbers into the equations.Note any wrong"solution".Explain how to solve the equation correctly.
1. 5r=320,r=64
2. 2x-3=13,x=8
3. 0.9x=7.2,x=8
2006-10-23 13:33:49 · 5 answers · asked by thelmadc06 1 in Science & Mathematics ➔ Mathematics
Sorry, I won't provide tyou the answer but I'll help you figure it out:
x=b/a... that should tell you which answers are valid & which are incorrect and what values must be assigned to make them "correct." Good Luck with all that!
Hint: A2. is x + b/a =0
2006-10-23 13:41:20 · answer #1 · answered by cherodman4u 4 · 0⤊ 0⤋
Sarge has explained A 1 and 2 very well
so to B
1. 5r = 320
here a = 5 and b = 320
x= b/a so x = 320/5 = 64
2. 2x-3 =13
we ahve to convert this to ax=b form
so add 3 to both sides of the equation
then 2x =16
a=2 b=16
as x = b/a = 16/2 =8
3. 0.9x = 2.7
a= 0.9 b = 7.2
so x =b/a = 7.2/0.9 = 72/9 =8
2006-10-24 06:43:44 · answer #2 · answered by grandpa 4 · 0⤊ 0⤋
1. r = 320/5
2. 2x = 13 +3 ... x = 16/2
3. x = 7.2/0.9
2006-10-23 20:43:39 · answer #3 · answered by steinmancloud9 2 · 0⤊ 0⤋
A.1. ax=b.... divide both sides by a
(ax) / a= b/a....the a's cancel out
x= b/a
|A.2.ax+b=0.... subtract bfrom both sides
ax+b-b=0-b
ax=-b ...divide both sides by a
(ax)/a = -b/a
x=-b/a
2006-10-23 20:48:46 · answer #4 · answered by Sarge 1 · 1⤊ 0⤋
a/b=x
2006-10-23 20:37:23 · answer #5 · answered by Anonymous · 0⤊ 0⤋