Answer for below questions for the following ion
F2+
a) how many electrons are in bonding orbitals?
b) how many electrons are in antibonding orbitals?
c) what is the bond order of the ion?
2006-10-23 13:29:48 · 2 answers · asked by MARK 2 in Science & Mathematics ➔ Chemistry
In a fluorine molecule F2, there are 18 total electrons, nine from each fluorine atom. In the monocation, there is one fewer electron, for a total of 17 electrons.
The molecular configuration for F2+ would be:
1sσ2 1sσ*2 2sσ2 2sσ*2 2pπ4 2pσ2 2pπ*3 where the σ* and π* molecular orbitals are the antibonding orbitals.
Therefore, there are 10 electrons in the bonding orbitals and 7 electrons in the antibonding orbitals.
The bond order = ½(#bonding electrons - #antibonding electrons) = ½(10-7) = 3/2
2006-10-23 15:43:33 · answer #1 · answered by Ravenwoodman 3 · 0⤊ 0⤋
a. seven in each F atom
b. six in each F atom
c. the F2+ means that one electron has been lost from the total 14 electrons that the F2 would share, leaving 13 electrons. Not sure what is meant by "bond order of the ion", as this is not a common expression in chemistry. It is a single bond (sharing two electrons).
The bond is a sigma bond, with sp3 hybridation.
2006-10-23 13:37:05 · answer #2 · answered by Alan Turing 5 · 0⤊ 0⤋