2006-10-23 11:55:04 · 4 answers · asked by Badiau M 1 in Science & Mathematics ➔ Mathematics
5C4=5 combinations
2006-10-23 11:57:27 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Do you mean combinations or permutations?
If you only want to pick 4 of the 5 digits, and order is irrelevant, then the answer is 5 (simply pick the one number to leave out). This can also be represented as 5C4 (5 choose 4) which is equal to: 5! / (5-4)! 4! ---> 120 / (1 * 24) = 5.
If you mean permutations, where order does matter, then it is more than this. You have 5 choices for the first digit, 4 for the second, 3 for the third and two for the last. It turns out this is equivalent to 5! (since the last digit is left out) or 120.
2006-10-23 12:35:53 · answer #2 · answered by Puzzling 7 · 0⤊ 0⤋
5c4
= 5
2006-10-23 12:09:05 · answer #3 · answered by luv_phy 3 · 0⤊ 0⤋
over 100
2006-10-23 12:05:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋