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A uniform door weighs 50.0 N and is 0.9 m wide and 2.7 m high. What is the magnitude of the torque due to the door's own weight about a horizontal axis perpendicular to the door and passing through a corner?

2006-10-23 11:49:58 · 2 answers · asked by David S 2 in Science & Mathematics Physics

2 answers

(0.9 / 2) x 50.0

= 22.5 Nm
(assuming the door is made from one material and of uniform thickness, so C.G. acts in the middle of the door.)

2006-10-23 12:54:32 · answer #1 · answered by luv_phy 3 · 0 0

I agree with the solution of luv_phy. Regards.

2006-10-24 17:15:14 · answer #2 · answered by tul b 3 · 0 0

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