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Solve the system by addition.
2x – 4y = 7
4x + 2y = 9

2006-10-23 11:44:58 · 7 answers · asked by Ash1227 2 in Education & Reference Homework Help

7 answers

2x-4y=7
4x+2y=9 (Multiply by 2)

2x-4y=7
8x=4y=18 (y's cancel out)

10x=25

x=2.5

SUBSTITUTE:

2(2.5)-4y=7
5-4y=7
-4y=-2

y=0.5

2006-10-23 11:48:59 · answer #1 · answered by Winner4600 3 · 0 0

alright I believe in order to solve this you want to get it so that either x or y cancels out when you add the equations together. An easy one to do is to multiply the bottom equation by 2 because then -4y would cancel with 4y and you'd only have one variable in the equation.
2x-4y=7
2(4x+2y=9)

2x - 4y = 7
+ 8x+ 4y=18
=10x+ 0y=25
Then you can solve for x and then plug x into one of the equations and solve for y.

2006-10-23 11:55:28 · answer #2 · answered by Anonymous · 0 0

Multiply the first equation by -2 to get -4x + 8y = -14.

Now ADD the two equations together. The x terms add up to zero, leaving

10y = -5, or y = -1/2

Multiply the second equation by 2 to get 8x + 4y = 18

Now ADD the two equations together. The y terms add up to zero leaving:

10x = 25, x = 2.5

2006-10-23 11:52:26 · answer #3 · answered by gp4rts 7 · 0 0

Work one problem at a time
2x-4y = 7
2x = 7+4y
x = 3.5+2y
(you cannot break down X any further, so apply it to the next one)
LIKE THIS
4x+2y = 9
4(3.5+2y)+2y = 9
14+8y+2y = 9
14+10y = 9
10y = -5
y = -1/2 (negative)
(this one is broken down completely, take the answer and apply it to the first equation)
LIKE THIS
2x - 4(-1/2) = 7
2x - (-2) =7
2x +2 = 7
2x = 5
x = 2.5
(now you have your final answer for X)
THEREFORE
X = 2.5
Y = -1/2

Plug in the numbers into your beginning equations to verify

2006-10-23 12:05:37 · answer #4 · answered by lexy5117 1 · 0 0

2x-4y=7
2(4x+2y)=2(9)
8x+4y = 18
10x=25
x= 2.5
2(2.5) -4y = 7
-4y=2
y= -.5

2006-10-23 11:58:07 · answer #5 · answered by CaptainObvious 7 · 0 0

2x-4y=7
8x+4y=18
10x=25
x=2.5
sub
5-4y=7
-4y=2
y=-0.5

2006-10-23 11:49:53 · answer #6 · answered by raj 7 · 0 0

tHere has to be at least one variable that is known to find the final answer, so you have both of those equations as the answer, I believe.

2006-10-24 12:23:56 · answer #7 · answered by X 4 · 0 0

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