7^5
- =
7^2
2006-10-23 10:39:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
7^5 / 7^2 = 7^(5-2) = 7^3 = 7x7x7 = 343
Explanation:
(7x7x7x7x7) / (7x7) = 7x7x7
Th
2006-10-23 10:46:39 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
Is this 7^5 divided by 7^2? You just subtract the exponents (but only if the base (the 7) is the same). In this case, the answer is 7^3.
2006-10-23 17:43:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If the base is the same, then subtract the exponents.
7^3 is the answer to that question.
2006-10-23 17:42:15 · answer #3 · answered by Your Best Fiend 6 · 0⤊ 0⤋
= 7^(5-2) | if you have same base on denominator and numerator
= 7^3 | then you substract power when you divide ( power of
= 343 | numerator - power of denominator)
2006-10-23 17:43:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋
7^(5-2) = 7^3
same thing as (a^b)/(a^c) = a^(b-c)
2006-10-23 17:42:04 · answer #5 · answered by Travis 4 · 0⤊ 0⤋