1999, 2001, 2003, 2005
i have to write a pattern rule for this pattern.
thank you
2006-10-23 09:48:34 · 4 answers · asked by havingfun 4 in Science & Mathematics ➔ Mathematics
odd numbers starting at 1999
n=2x+1997
2x (the number it goes up by each time times the term number)
1997 (The 0th term)
2006-10-23 09:58:48 · answer #1 · answered by tydietyler 3 · 0⤊ 0⤋
N(i)=N(i-1)+2
2006-10-23 09:52:11 · answer #2 · answered by Vincent G 7 · 0⤊ 0⤋
use this formula Xn=a+b(n-one million) a=first term b=diference between the words enable me teach u and occasion for the 1st one 7,25,seventy 9,241,727 we've this so enable substract the 2d via the 1st one b=25-7=18 now plow it in a=7 Xn=7+18(n-one million) simplify Xn=7+18n-18 Xn=18n-11 it extremely is the development for the 1st development regulations 2)24n-12 3)4-4n n is in simple terms the variety of the term interior the series to illustrate 7 ,25 ,seventy 9 ,241 ,727 one million 2 3 4 5 so if u plow 3 on the 1st equation it has to grant u seventy 9
2016-12-16 13:08:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
well, an evident possibilty is you have an arithmetic progression with constant 2 ands first term 1999. If thats the case (there are infinitely many possibilities), for every n= 1,2,3.... we have a_n = 1997 + 2n
2006-10-23 10:07:46 · answer #4 · answered by Steiner 7 · 0⤊ 0⤋