I need help with these math questions?

Question

Solve the equation
9y/y-10+7=2y/y-10

And
t/t-4=t+4/-6

Answer 1

when you have solved them
post the answer

Answer 2

Are you sure you put the eqn correctly including any braces?

1. 9y/y-10+7=2y/y-10
=> 9 - 10 + 7 = 2 - 10
=> 6 = -8
So obviously you didn't put your question correctly

And
t/t-4=t+4/-6
=> 1 - 4 = t +4/-6
=> -3 = t + 4/-6
=> t = -3 - (4/-6)
=> t = -3 +4/6
=> t = -14/6 ---- apparently not the solution you are looking for.

Answer 3

Please use parentheses to clearly identify what is in the denominator.

I'll assume that the first equation is
9y/(y-10) + 7 = 2y/(y-10).

Then (9y-2y)/(y-10) = -7, so 7y/(y-10) = -7, or y/(y-10) = -1. Multiply both sides by y-10 and get

y = -(y-10), so y = -y + 10, meaning 2y = 10, so y=5.

I assume the second equation is t/(t-4) = (t+4)/-6.

Multiply both sides by t-4: t=(t+4)(t-4)/-6.
Multiply both sides by -6: -6t = (t+4)(t-4)
Multiply out right side: -6t = t^2 - 16
Rearrange: t^2 + 6t - 16 = 0
Factor: (t+8)(t-2) = 0
So t=-8 or t=2.

Answer 4

If the terms have a common denominator, you could combine them. So, multiply the 7 by (y - 10)/(y - 10).
This will give you:
9y/(y - 10) + 7(y - 10)/(y - 10) = 2y/(y - 10)
Since all the denominators are the same, you can look at the numerators now:
9y + 7(y - 10) = 2y

Now, this equation should be easy to solve.

For the second equation, since it's set up as a proportion, why don't you cross-multiply, then solve.

Answer 5

Assuming you mean (9y/(y-10))+7=2y/(y-10)

9y + 7 2y
---- = -------
y-10 y-10

Multiply by (y-10) throught gives

9y + 7(y-10) = 2y
y=5

I'll let you do the other one...

Answer 6

1 - multiply both sides times y-10... so 9y+7y -70=2y...then 16y-70=2y then...
14y-70=0 then...
14y=70
y=70/4
y=5

2: cross multiply then factor
-6t = (t+4)(t-4)
-6t = t^2 - 16
0 = t^2+6t-16
0=(t+8)(t-2)
so t= -8,2