How would I give the name for a quadrilateral with these given vertices.
A(-4, -2) B(5, 4) C(7, 1) D(-2, -5)
P(-2, 3) Q(3, 4) R(4, -1) S(-1, -2)
Aren't I suppose to use the distance formula, and do it by Line AB, BC, CD, AD? Figure those two out for me anyone, thanks.
2006-10-23 09:08:06 · 2 answers · asked by bosshog 1 in Science & Mathematics ➔ Mathematics
The first thing I always do (especially when the numbers are all small like the ones you have) is graph them out and label them. This will give you a visual image of what you are trying to solve. I would do this for you, but then it would be hard to transmit the information to you via Yahoo! Answers. I hope this helps.
By the way, slopes are simply (y2 - y1)/(x2 - x1), so your slopes are:
AB = 6/9 = 2/3
BC = -3/2
CD = -6/-9 = 2/3
DA = -3/2
So, your opposite lines are parallel (which is nice), and your slopes are inverses (which is nice, too). The distances will determine whether this is a square or a rectangle.
2006-10-23 09:14:03 · answer #1 · answered by Dave 6 · 0⤊ 0⤋
Slope of AB = 4-(-2)/5-(-4) = 6/9 = 2/3
2006-10-23 16:17:59 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋