chemistry question: dealing with finding the avg atomic mass and abudance..?

Question

This is the q: There are 2 different isotopes for element Nailium. A representive sample of Nalium is in the container; there are 350 nails total. What is the (average) atomic mass of Nalium? What is the % abudance of each isotope in the mixture? How many white and black nails are in the container?

This is the information that was given to me:

* This is the equation used to solve the problem:
(abundance as a decimal x mass of all isotopes)

Mass of representive sample = 212.1 g

Mass of one white nail= .42 g

Mass of one black nail=.71 g


Please help thankz

Answer 1

Let number of white = x
number of black = y

x+y = 350
.42x + .71y = 212.1

And solve.

Answer 2

you recognize which you have 350 nails entire. you recognize what each form of nail weighs, and the finished mass. Making x the variety of white nails, and y the variety of black nails, you ought to use a gadget of equations to sparkling up for the variety of each colour of nail. as quickly as you are trying this, you will locate the % abundance by way of dividing the variety of each nail by way of the finished form of nails. Your numbers ought to upload as much as a million (or a hundred%).