2006-10-23 07:14:20 · 8 answers · asked by Smiley22 1 in Science & Mathematics ➔ Mathematics
False
sqrt(2) is irrational
sqrt(8) is irrational
sqrt(2)8sqrt(8)=sqrt(16)=4 is rational.
2006-10-23 07:17:43 · answer #1 · answered by yupchagee 7 · 19⤊ 0⤋
I will not just show you an answer, but HOW to find an answer.
Take some random irrational numbers: √2, √3, ... and see what happens when you multiply them.
√2 x √3 = √6 which is also irrational.
But, don't forget:
√2 x √2 = 2 which is rational, so the answer is False.
Here is a more direct way. What is the simplest irrational number you know? √2 ?
OK, so find an irrational x so that (√2) x = rational. What is the simplest rational number? How about 1?
So, if (√2) x = 1 then x = 1 / (√2). Is that irrational? You can simplify it to (√2) / 2 which must be irrational because √2 is irrational.
2006-10-23 07:38:40 · answer #2 · answered by p_ne_np 3 · 3⤊ 0⤋
False. Take sqrt(2) and 3/sqrt(2). Both are irrational and their product is the rational 3.
You should keep im mind the following:
The product of 2 rational numbers is rational
The product of a irrational number by a rational number different from 0 is irrational
The product of 2 irrational numbers can be rational or irrational
2006-10-23 07:53:13 · answer #3 · answered by Steiner 7 · 0⤊ 0⤋
Definitely false. Take any irrational number and multiply it by it's inverse, which will also be irrational. You'll get 1 every time.
2006-10-23 07:22:54 · answer #4 · answered by metatron 4 · 3⤊ 0⤋
False. sqrt 2 x sqrt 2 = 2
2006-10-23 07:39:25 · answer #5 · answered by davidosterberg1 6 · 3⤊ 0⤋
Imaginary numbers have a term for i , i=squareroot of ( -1 ) Real numbers have no i
2016-05-22 01:41:53 · answer #6 · answered by Anonymous · 0⤊ 0⤋
false
sqrt(2) * sqrt(2) = 2
2006-10-23 07:52:05 · answer #7 · answered by gjmb1960 7 · 2⤊ 0⤋
false
rt3*rt3=3
2006-10-23 07:20:26 · answer #8 · answered by raj 7 · 3⤊ 0⤋