(x + 2) (x - 3)
First figure out how to get 6. You could either use 6 x 1 or 3 x 2. 3 x 2 is the best choice because you get -1 if you subtract 3 from 2 (which is what you want in the middle term. Then you have to note that x^2 can only come from 2 x's so you put that in the beginning. The nest step is figuring out where to put your + and - . In this equation the + goes with the 2 and the - goes with the 3 because it equals -1 when put together.
2006-10-23 07:11:32
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answer #1
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answered by Christine D 1
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X= -2
or X=3
2006-10-23 05:36:48
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answer #2
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answered by Anonymous
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It's like this
x^2-x-6
(x-3)(x+2)---;reason: -3+2 = -1 -3*2 = -6
(x-3)(x+2)
the factors are 3 & -2
2006-10-23 06:25:50
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answer #3
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answered by Aq 3
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(x - 3)(x + 2)
2006-10-24 00:56:22
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answer #4
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answered by lykovetos 5
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(x^2-x-6) = (x-3)(x+2)
2006-10-23 05:36:24
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answer #5
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answered by mr_mumbles_nyc 3
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x^2-x-6
Since -3 and 2 equals to -6 and -3+2=-1, the problem would look like this:
(x-3)(x+2)
Check:
(x-3)(x+2)=
x^2-3x+2x-6=
x^2-x-6
2006-10-23 06:50:17
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answer #6
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answered by Anonymous
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this is easy one
(x-3)(x+2)
so the value of x are 3 and -2
2006-10-23 05:40:17
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answer #7
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answered by Khalidxp 3
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(x+2)(X-3)
2006-10-23 05:38:20
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answer #8
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answered by Ashi 2
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(x2-x-6)
=x2-3x+2x-6
=x(x-3)+2(x-3)
=(x+2)(x-3)
this method is called splitting the middle term
u could also use factor theorem
2006-10-23 05:43:56
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answer #9
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answered by sushobhan 6
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-6
2006-10-23 05:41:34
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answer #10
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answered by Anonymous
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