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The question is; "Draw the structure of the oxime derived from ethanal. Suggest why the oxime and semicarbazone of ethanal are solids whereas the aldehyde is liquid."

So far I have the structure of the oxime of ethanal to be CH3CH=NR' but I have no idea what a semicarbazone is (not in my textbook)Can anyone please help me ! :)

2006-10-23 05:06:30 · 4 answers · asked by Showaddywaddy 5 in Science & Mathematics Chemistry

4 answers

Compounds having the structure R. 2. C=NNHC(=O)NH. 2. , formally derived. by condensation of aldehydes or ketones with semicarbazide ...

2006-10-23 05:21:33 · answer #1 · answered by raj 7 · 0 1

Use of a semicarbazone plant growth regulator for early termination of crop plants
Document Type and Number: United States Patent 6284711
Link to this Page: http://www.freepatentsonline.com/6284711.html
Abstract: Late season termination of reproductive plant growth of a plant having an indeterminate growth pattern is achieved by the application of a semicarbazone plant growth regulator to a locus of a growing plant at a time following peak bloom of the plant. The semicarbazone is applied as an active ingredient in an amount sufficient to terminate continued reproductive growth of the plant without substantially affecting mature reproductive growth existing on the plant at the time of application. Most preferably, the semicarbazone

2006-10-23 12:12:14 · answer #2 · answered by Anonymous · 0 1

In organic chemistry, semicarbazone is a derivative of semicarbazide which contains an additional ketone functional group. Their structure is R2C=NNHC(=O)NH2. A 'thiosemicarbazone' contains an sulfur thio atom (sulfur) in lieu of the ketonic oygen. Both semicarbazones and thiosemicarbazones are known to have anti-viral and anti-cancer activity, usually mediated through binding to copper or iron in cells.

2006-10-23 12:09:40 · answer #3 · answered by Anonymous · 1 0

Its where all those half cars cant go

2006-10-23 12:14:14 · answer #4 · answered by Anonymous · 0 3

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