2006-10-23 02:56:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It is an even function, because g(x) = |x| = x
and g(-x) = |-x| = x too.
2006-10-23 02:58:32 · answer #1 · answered by F.G. 5 · 1⤊ 0⤋
The way to define if a function is even or odd is to plug in (-x) for x, and see the result. If g(-x) = x, then the function is even. If g(-x) = -x, then the function is odd. If you get neither as the result, then the function is neither. THIS IS ONLY WITH RESPECT TO THE ORIGIN. A function can also be even or odd if a constant is eleminated in the end, i.e. x+5 is odd, or x^2-4 is even.
Here, if g(x) = |x|, then
g(-x) = |-x| = x,
so g(x)= |x| is EVEN
2006-10-23 03:11:13 · answer #2 · answered by Mr. Chemistry 2 · 0⤊ 0⤋
It's even, because g(-x) =|-x| = |x| = g(x) for every real x.
2006-10-23 03:08:12 · answer #3 · answered by Steiner 7 · 0⤊ 0⤋
neither, because it has a absolute value
2006-10-23 04:32:29 · answer #4 · answered by arpalu69 1 · 0⤊ 0⤋
even
since
g(-x)=g(x)
2006-10-23 04:14:49 · answer #5 · answered by locuaz 7 · 0⤊ 0⤋