2006-10-23 02:36:24 · 4 answers · asked by Donna G 1 in Science & Mathematics ➔ Chemistry
Mg is divalent, so its equiv wt is half its atomic wt.
Which means the Normality of its solns is twice the Molarity.
Hence 0.003 M is 0.006 N (meq/l)
2006-10-23 03:09:10 · answer #1 · answered by L. A. L. 6 · 0⤊ 2⤋
Your question as it is, makes no sense.
Equivalents are defined according to the reaction in question.
The same amount of a compound can have different normalty depending on whether the equivalent is for an acid-base reaction, a redox, reaction (or a complexation reaction)
If it is a solution of Mg(OH)2, then as a base it has 2*3*10^-3= 6 *10^-3 eq/L = 6 meq/L since there are 2 OH- per molecule
If it is a solution of Mg2+ that is going to be reduced to Mg again it is 2*3= 6 meq/L since each ion takes 2e
If it is a complexation reaction, I think Mg2+ has usually coordination number 6 , thus it would be 6*3 =18 meq/L
Normality = a*molarity
where a is the
-number of H+/OH- for acid/bases
-number of e taken or given during redox reactions
-coordination number for complexation reactions
2006-10-23 04:57:46 · answer #2 · answered by bellerophon 6 · 0⤊ 1⤋
because Mg2+ carries 2 positive charges, it is 2 times 3*10^-3 M= 6 * 10^-3 meq/L
2006-10-23 04:34:17 · answer #3 · answered by arifin ceper 4 · 0⤊ 0⤋
42
2006-10-23 02:38:29 · answer #4 · answered by fugue.state 2 · 1⤊ 0⤋