I'm on the last question for my homework and I don't get how to do it, here it is...
An unknown element named Renegadium (Rg) consists of four isotopes Rg (A) mass # 281, Rg (B) mass # 282, Rg (C) mass # 283, Rg (D) mass #284. Isotopes C has a percentage abundance of 2.00%. Isotopes A and D have the same percentage abundance. Calculate the percent abundance of A, B and D.
2006-10-23 00:34:10 · 4 answers · asked by Silentspeedster 2 in Science & Mathematics ➔ Chemistry
I don't have time to work out the numbers at this moment, but the best advice I could give is to use the fact that mass number is the sum of the percent compositions of all the naturally forming isotopes of an element. Maybe you can get a formula from that.
2006-10-23 01:07:20 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You need to know the atomic weight of Rg. Let's call this W. If x is the proportion of A and D (measured in percentage divided by 100), then x = W - 282.02. Once you find the value of x, multiply by 100 to get the % abundance of A and D. You already know the abundance of C, so B is 100 minus the other three percentages that you will have.
2006-10-23 08:07:59 · answer #2 · answered by JJ 7 · 0⤊ 0⤋
I don't think that there is enough information here. What does the question say about B?
2006-10-23 07:48:23 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋
You are in which class?
2006-10-23 07:41:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋