2006-10-22 23:55:11 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3x squared - 6 or 3x^2 -6
= 3(x^2-2)= 3(x^2-(sqrt2)^2)
=3(x-sqrt 2)(x+sqrt 2) because a^2- B^2 = (a-b)(a+b)
sqrt= square root of
simple ! :)
2006-10-22 23:59:27 · answer #1 · answered by manshul2001 2 · 0⤊ 0⤋
3x square - 6 = 3 ( x square - 2 )
2006-10-23 00:12:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
it somewhat is terrific to artwork out with factoring decomposition, despite if this is plenty swifter to element by way of ideas. it easily relies upon on the way you opt to unravel each and each difficulty. a) (x - 2)(x + 3) = 0 x - 2 = 0 and x + 3 = 0 x = {2,-3} b) (x - 3)(x + 8) = 0 x - 3 = 0 and x + 8 = 0 x = {3,-8} c) (x - 4)(x - 2) = 0 x - 4 = 0 and x - 2 = 0 x = {4,2} d) (x - 7)(x + 4) = 0 x - 7 = 0 and x + 4 = 0 x = {7,-4} i'm hoping this helps! ?????? ??????? ??????
2016-12-08 19:32:10 · answer #3 · answered by daies 4 · 0⤊ 0⤋
3x^2 - 6
= 3(x^2 - 2)
That's about as far as you can go unless you use square roots.
= 3[x - sqrt(2)][x + sqrt(2)]
2006-10-23 00:04:48 · answer #4 · answered by falzoon 7 · 1⤊ 0⤋
Put brackets in.
3xsquared - 3, 1, x, x (factors of 3xsquared)
6 - 6, 1, 2, 3 (factors of 6)
Highest common factor = 3
(HCF goes outside the brackets).
3(xsquared - 2)
Hope this helps.
2006-10-23 00:02:10 · answer #5 · answered by Michelle 3 · 0⤊ 0⤋
3x² - 6 = 3(x² - 2)
= 3(x - sqrt(2) )(x + sqrt(2) )
2006-10-23 01:13:35 · answer #6 · answered by heliopolis_sapiens 1 · 0⤊ 0⤋
3x^2-6=3(x^2-2) =3(x+sqrt2)(x-sqrt2)
2006-10-23 00:03:16 · answer #7 · answered by grandpa 4 · 0⤊ 0⤋
3x^2-6
=3[x^2-2]
=3[x+sqrt2][x-sqrt2]
2006-10-23 00:09:52 · answer #8 · answered by openpsychy 6 · 0⤊ 0⤋
3x^2-6=3(x^2-2)=3(x-(2)^(1/2))(x+(2)^(1/2))
2006-10-23 00:04:18 · answer #9 · answered by mathman241 6 · 0⤊ 0⤋