help me solve these algebra problems?

Question

3a^2/2a
6a^3+3a^2/3a
6a^2+3a^2/3a
4y^3+2y^2/2y
9X^2Y^2-4A^2B^2/3xy-2ab

Answer 1

3a^2/2a =(3/2)a
6a^3+3a^2/3a =3a^2(2a+3)/3a=a(2a+3)
6a^2+3a^2/3a =9a^2/3a=3a
4y^3+2y^2/2y =2y^2(2y+1)/2y=y(2y+1)
9X^2Y^2-4A^2B^2/3xy-2ab =(3xy+2ab)(3xy-2ab)/3xy-2ab
=3xy+2ab

Answer 2

1) 3a/2 ( a isn't 0 )
2) 6a^3 +a = a(6a^2 +1)
3) 6a^2 + a = a(6a + 1)
4) 4y^3 + y = y(4y^2 + 1)
5) it won't make sense unless it's: (9X^2Y^2-4A^2B^2/3xy) / (3xy-2ab) the answer is:
(3xy - 2 ab)(3xy + 2ab)/ (3xy - 2ab) = 3xy + 2ab

Answer 3

1.) 3a/2 for a<>0
2.)6a(a^2+1)

3.) y(1+4Y^2)

4.)FORGETIT or if
9x^2y^2== (3xy)^2,

so 3xy+2ab if 3xy-2ab<>o

Answer 4

1. 3a/2
2. a ( 6a^2 +1 )
3. a ( 6a + 1 )
4. y ( 4y^2 + 1 )
5. sry I'm not sure

Answer 5

3a^2/2a=3a*a/2*a=3a/2

6a^3+3a^2/3a= 6a^3+3a*a/3a=6a^3+3a
If it is (6a^3+3a^2)/3a which is what you meant
= 6a*a*a/3a+3a*a/3a
= 6a^2+3a
=3a(a+1)

6a^2+3a^2/3a= 6a^2+3a
if (6a^2+3a^2)/3a
= 9a^2/3a
= 3a

i am attempting other probs the same way
(4y^3+2y^2)/2y
=4y^3/2y+2y^2/2y
=2y^2+y
=y(2y+1)

(9x^2y^2-4a^2b^2)/(3xy-2ab)
={(3xy-2ab)(3xy+2ab)}/(3xy-2ab)
=3xy+2ab

Answer 6

is the first one (3a)^2/2a or 3(a^2)/2a?

Answer 7

3a²/2a = 3a/2

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6a³ + 3a²/3a =

6a³/3a + 3a²/3a =

2a² + a

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6a² + 3a² / 3a =

6a² / 3a + 3a² / 3a =

2a + a

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4y³ + 2y²/2y =

4y³ / 2y + 2y² / 2y =

2y² + y

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Answer 8

i'm only a fourth grader!