A filter apparatus is submerged in rectangular fish tank A, raising the water level by 1 cm. When the same filter is submerged in fish tank B, the water level is raised only 0.5 cm. If the fish tanks have the same water level without a filter, what is the ratio of the top water surface of tank A to the top water surface of tank B?
2006-10-22 19:17:04 · 3 answers · asked by Stuck 1 in Science & Mathematics ➔ Mathematics
Equal volumes of water are displaced by the filter, so
A(A)*1 = A(B)*(1/2)
A(A)/A(B) = 1/2
2006-10-22 19:24:07 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
the filter dispaces the same volume of water
volume = surface area * height
since in the fish tank B height is raised by only half the fish tank A,
surface area of B has to be twice the surface area of A to have the same displaced volume
so ratio of top water surface of A :B:: 1:2
2006-10-23 04:24:20 · answer #2 · answered by grandpa 4 · 0⤊ 0⤋
The same volume is displaced in both tanks. So if the level rise in tank A is double the level raised in tank B (1 cm vs 0.5cm) then the surface area of tank B is double that of tank A.
2006-10-23 02:26:09 · answer #3 · answered by Jimbo 5 · 0⤊ 0⤋