The favorable outcomes over the overall outcomes in the circular spinner. This is year 8 stuff.
2006-10-22 17:48:06
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answer #1
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answered by Martin I 1
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In the classic example of a spinner with equally divided red, blue, green and yellow sections, the probability of landing on any particular color is the portion of the spinner of that color over the total portions or total chance on the spinner.
However, if the portions are inequal, and you know the measurements of the sections (e.g. a pie chart) then those can be converted into a fraction from the percentage.. for example a 38% on a pie chart could be expressed as 38/100 or reduced to roughly 2/5.
If you don't know the measurements of the angles I'm sure there's a means by which you could find them out, I'm just not sure I know them yet (11th grade math)
2006-10-22 18:00:57
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answer #2
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answered by Anonymous
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Suppose you have a circle divided into N equal wedges. n of the wedges represent a favorable outcome, call it a win.
Then,
P(win) = n/N
P(no win) = (N-n)/N
If, as in Wheel of Fortune, there are m results that are losses,
P(loss) = m/N
P(no loss) = (N-n)/N,
and, finally,
P(no win and no loss) = (N-m-n)/N
2006-10-22 18:02:27
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answer #3
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answered by Helmut 7
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