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2 answers

-2 (sin2x)^2 - 2 (cos2x)^2 = -2 ( (sin2x)^2 + (cos2x)^2 )

= -2 * (1) = -2

2006-10-22 16:57:25 · answer #1 · answered by z_o_r_r_o 6 · 2 1

sin 2x (- 2 sin 2x) - 2 cos 2x (cos 2x)
= -2 [(sin 2x)^2 + (cos 2x)^2 ] = -2

2006-10-23 03:03:41 · answer #2 · answered by locuaz 7 · 0 0

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