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5 answers

n = (n^2-7)n^3

2006-10-22 15:34:41 · answer #1 · answered by pokerden1 2 · 0 0

n = n^3(n^2 - 7)

2006-10-22 16:05:35 · answer #2 · answered by maggie_at0303 3 · 0 0

n = (n^2 - 7)n^3

2006-10-22 15:34:15 · answer #3 · answered by Marcella S 5 · 0 0

Hi. Does this look right? n=(n^2 + 7)-(n^3)

2006-10-22 15:37:49 · answer #4 · answered by Cirric 7 · 0 0

n = (n^2 -7) *(n^3)

* is times (multiplication)

2006-10-22 15:34:52 · answer #5 · answered by Anonymous · 0 0

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