3.25M HNO(3) solution needs to be mixed with 50.0mL 6.00M HNO(3) solution to form a 4.50 M HNO(3) solution

Question

What volume of 3.25M HNO(3) solution should be mixed with 50.0mL of 6.00M HNO(3) solution in order to form a 4.50M solution of HNO(3)?

Answer 1

60 mL

3.25 * X + 50 * 6 = total moles

4.5 = total moles/ x +50
4.5 X + 225 = 3.25 X + 300
1.25 X = 75
X = 60