A hockey puck moving along the +x axis at 0.41 m/s collides into another puck that is at rest. The pucks have equal mass. The first puck is deflected 35 below the +x axis and moves off at 0.38 m/s. Find the speed and direction of the second puck after the collision.
2006-10-22 13:41:49 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Remember that momentum is conserved, so calculate the momentum of the 1'st puck before and after the collission (easy, since the y axis momentum was 0). Now calculate the x axis momentum of the 2'nd puck as the difference of the before and after x axis momentum of the 1'st puck, and the y axis momentum as the negative of the 1'st pucks momentum after the collision (since they have to sum to 0) Once you have those, the x and y velocities of the 2'nd puck are known and it's just transforming to polar coordinates..
Doug
2006-10-22 13:53:43 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋