2006-10-22 12:10:07 · 6 answers · asked by MR T M 1 in Home & Garden ➔ Other - Home & Garden
And the average hight of a cloud is?
2006-10-22 12:16:26 · answer #1 · answered by Billy 2 · 0⤊ 0⤋
It relies upon on 2 issues - how intense the clouds are and how briskly the raindrops are falling. Fog isn't something extra beneficial than cloud at floor point so if this is foggy and raining on the comparable time the raindrops could have fallen in ordinary terms a short distance and could attain the floor in in ordinary terms some seconds. on the different intense are some thunderclouds that can improve upwards to 20km (12 miles) if a raindrop fell from the precise of one of those clouds and descended at 5 metres according to 2d (18kmh / 11mph - common velocity for a raindrop) then it may take a sprint over an hour to attain the floor. often a raincloud possibly one thousand metres (3000 ft) above the floor, raindrops from this height could take 2 to 5 minutes to fall to the floor (relies upon on the size and shape of the raindrop).
2016-12-08 19:17:13 · answer #2 · answered by barsky 4 · 0⤊ 0⤋
Me thinks
s=ut+1/2at/squared
Where s is height of cloud
u is intial speed which we will take as 0
a is acceleration which is always 9.81m/s
and t is time
Therefore if average cloud is 1000 meters up
1000=0xt + 1/2 x 9,81 x t squared
t squared =1000/4.91
t = approx 14.15 secs maybe????
2006-10-23 05:01:49 · answer #3 · answered by clansman 1 · 0⤊ 0⤋
I'll bet it is 32 feet per second, squared. The height of the cloud, I will leave up to you. - Chris.
2006-10-22 12:17:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Too many variables. Droplet size, winds, temps, elevation, pressures.
2006-10-22 23:44:11 · answer #5 · answered by william v 5 · 0⤊ 0⤋
I suppose it depends on the size of the raindrop.
2006-10-22 12:20:26 · answer #6 · answered by Matt 2 · 0⤊ 0⤋