show work please 4-2x^2=12?

Question

show work please

Answer 1

4-2x^2=12
-2x^2=8
X^2=-4
+/- 4i (i is imaginary number equal to sqrt(-1))
if you're in a math class where you haven't learned about "i", then the answer is "no solution"

Answer 2

4-2x^2=12=>2x^2=8=>x^2=4=>x=2 or x=-2

Answer 3

4-2x^2=12

so, (4-2x^2)-4=12-4 Subtract 4 from each side

then, (-2x^2)/-2=(8)/-2 Divide each side by -2

finally, (-x^2)^(1/2)=(-4)^(1/2) Raise each side to the 1/2

Therefore, x = 2i (square root of a negative is tricky)

Remember, exponents first, then mult/div, then add/sub. To solve, do it in reverse.

Answer 4

4-2x^2=12
+4 +4
-2x^2=8
divide by -2 onboth sides
x^2=-4
Square root of negative 4 is 2i whereas i is an imaginary number

Answer 5

4-2x^2=12
subtract 4 from each side leaving you with:
-2x^2=8
divide both sides by -2 giving you:
x^2=-4
the take the square root of both sides:
x=+2squareroot(-1) and x=-2squareroot(-1)

Answer 6

4-2x^2=12
subtract 4 from each side
-2x^2=8
divide each side by -2
x^2=-4

x = -2i , +2i

Answer 7

4-2x^2=12
2x^2=8
x^2=4
x=2