4.
The 2 you can see that are alive, & the 2 you can't see that are inside the other two.
2006-10-22 05:21:55
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answer #1
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answered by Anonymous
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2?
Odd question...
Best Wishes...
T.
****EDIT****
Is this a trick question?
OK, I am dumb... this is impossible equation... The two fish can't eat the other two fish, that would require six fish in the tank to be possible...
Fish A eats Fish C and Fish D
Fish B eats Fish E and Fish F
If that is what you are getting at, then I get it now...
The only combination would be two of the fish eat one fish each... but technically, both can't eat two whole fish. They could share though, each eating 1/2 a fish, so both "fish ate the other two" fish would be a true statement...
Fish A eats 1/2 of Fish C and 1/2 of Fish D
Fish B eats the other half of Fish C and Fish D
Or, I am way over analyzing your question....
:)
T.
2006-10-22 12:17:12
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answer #2
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answered by Theophania 4
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2 fish
2006-10-22 12:16:55
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answer #3
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answered by Mmmmmmmxxxi 2
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Can't you just count how many fish are left in the tank?
2006-10-22 12:18:28
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answer #4
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answered by Anonymous
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2 FISH A RED FISH AND A BLUE FISH
2006-10-22 12:24:05
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answer #5
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answered by JESS B 1
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None, assuming a fish could eat itself.
2006-10-22 14:56:50
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answer #6
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answered by Anonymous
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Look, i know u just had TWO fried fish!
2006-10-22 12:23:48
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answer #7
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answered by novembr 5
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You would have a 2-piece Fish n Chips!!!!!!!!!!
2006-10-22 14:27:50
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answer #8
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answered by Army Of Machines (Wi-Semper-Fi)! 7
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2 would be left then if the one of the ones that r still alive will most likely eat the other alive one
2006-10-22 12:17:45
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answer #9
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answered by diethings 2
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0..hmmm..wait...wht kinda fish do u actually hav?? shark/?!!..i havent heard of aquarium fishes eatin each oder..!
2006-10-22 12:19:20
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answer #10
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answered by jumz 2
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