is this correct????

Question

suppose you have a coin collection of dimes and quarters containing 46 coins. if you have $6.70 how many of each type do you have:
quarters=25cents dimes=10cents
25*24=600 10*7=70

600+70=670 ??

Answer 1

Dave has the right idea, and his math is correct, but he skips a number of steps and I'm afraid you will just take the answer and run, instead of learning how to do it.

Now, set up the equation so you have the correct parameters:

Instead of X and Y, we can use Q for Quarters and D for Dimes.

You have 46 coins, worth 25 cents and 10 cents, respectively, for a total of 670 cents, so that you have 2 equations:

Q + D = 46
25Q + 10D = 670.

The smallest common factor for Q and D is 10, and we can use that to determine a greater range of values, by multiplying the above top equation by 10 to show that:

10Q + 10D = 460.

and you can subtract these values from the values in your first equation:

25Q - 10Q = 15Q
10D - 10D = 0
670 - 460 = 210.

So, 15Q = 210, and dividing each side by 15 (to determine the total number of quarters which make up 210 cents):

Q = 14. There are 14 Quarters, and 46 coins minus 14 coins equals 32 coins, so there must be 32 dimes.

46 - 14 = 32. And,

14(25) + 32(10) = 350 + 320 = 670.

So that 14 quarters and 32 dimes equals 46 coins and $6.70

(Above, instead of using 10 as the first multiplier, you could have used 25, and still arrived at the same final answer). Perhaps you should try that for practice.

Answer 2

Let

q = quarters

d = dimes

46 = total coins

.25q = The value amount of quarters

.10d = the value amount of dimes

6..70 the combines value

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Multiply the equation by 100

.25q + .10d = 6.70

100(.25q) + 100(.10d) = 100(6.70)

The new equation

25q + 10d = 670

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25q + 10d = 670 - - - - - -Equation 1

q + d = 46 - - - - - - - - - -Equation 2

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Substitute Method Equation 2

q + d = 46

q + d - q = 46 - q

d = 46 - q

Insert the d value into equation 1

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25q + 10d = 670

25q + 10(46 - q) = 670

25q + 460 - 10q = 670

15q + 460 = 670

15q + 460 - 460 = 670 - 460

15q = 210

15q/15 = 210/15

q = 14

The answer is q = 14

insert the q value into equation 2

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q + d = 46

14 + d = 46

14 + d - 14 = 46 - 14

d = 32

The answer is d = 32

Insert the d value into equation 2

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Check

q + d = 46

14 + 32 = 46

46 = 46

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Check equation 1

25q + 10d = 670

25(14) + 10(32) = 670

350 + 320 = 670

670 = 670

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Answer 3

Nope. You can set this up as follows, with x for quarters and y for dimes:
x + y = 46 and 25x + 10y = 670 (taking out the decimals)
solve for x in the first equation x = 46 - y and plug that into the second: 25(46 - y) + 10y = 670. so 1150 - 25y + 10y = 670. leaving you with -15y = -480 which is the same as 15y = 480 so y = 32. put that in the first equation, X + 32 = 46, so x = 14....

Answer 4

No. Let Q be the number of quarters and D be the number of dimes:

Q + D = 46
25*Q + 10*D = 670

Multiply the first one by 10 and subtract it from the second:

15*Q = 210
Q = 14

Substitute this back into the first equation:

D = 46 - 14 = 32

So, you have 14 quarters and 32 dimes.

Answer 5

quarter =25 cents dime=10 cents
dollar=100 cents
let x be the no. of dimes
let y be the no. of quarters

x+y=46-------------1


total amt. =6.70$ =670 cents

therefore,
10x +25y=670---------------2

solving equation 1 & 2 simultaneously,


x+y=46

y=46-x

therefore
10 x+ 25(46-x)=670
10x + 1150-25x=670
-15x=670-1150

-15x= -480

x= 32
from eq 1 , y=46-x
y=46-32=14
y=14
Answer: There are 32 dimes and 14 quarters
hope this helps.
best regards,

Answer 6

I would probably not correct him as I didn't give him the command. Isn't the point of learning these commands is to do then when the command is given? Wouldn't it almost be like the dog dictating commands and now you're following his lead instead of the other way around? My dog will sometimes speak when he wants a treat, even though none were offered. If I played along and have given him the treat, it now turns into him not earning his treat on my terms, but demanding the treat and being rewarded for it. Then I would think if you didn't give the command and he was just laying down to lay down and then was reprimanded for coming out of the stay, I would think that would be confusing to the dog.

Answer 7

14 quarters and 32 dimes

Answer 8

since when does 24 and 7 equal 46....use a system of equations

go (.25x) + (.1y) = 6.70

and x+y=46

now substitute

y= 46-x

so plug that to the originial...solve for one of the variables and then plug to get the other

Answer 9

no because your total number of coins doesn't equal 46

an equation for help:

25x+ 10Y= 670
x+Y=46

Answer 10

Yes that is correct