How do I graph one over square root of x?

Question

over domain [0,100]

Answer 1

As x increases, the function value get closer and closer to
the x axis both from above the axis and below it. We say the line
approaches the x-axis asymptotically. At x=1, f(x) is both 1 and -1.
As x get smaller, approaching 0, the function rises towards the y-
axis above the x-axis and falls towards the y-axis below the x-axis. It never touches the y-axis, but approaches it asymptotically
both positively and negatively.

Answer 2

Make a table and plot points. Y = 1/sqrtX
If X=100, Y=1/10
If X = 1, y = 1
If X = 64, Y = 1/8
etc.
At X = 0, it goes to infinity, or is undefined because you are dividing by zero.

Answer 3

y=1/x is undefined at x=0, but you can graph it at points very close to zero. Make up a chart as follows:

x = 100, y = 0.01
x = 50, y = 0.02
x = 10, y= 0.1
x = 1, y = 1
x = 0.5, y = 2
x = 0.1, y = 10
x = 0.01, y = 100
x = 0.001, y = 1000

So as x gets smaller and smaller, y gets larger and larger, but x can never = 0. So the graph starts out with x very close to zero with y enormously large. As x increases, y becomes smaller and at x= 1, y= 1.Then as x increases from 1 to 100, y continues to shrink, being only 0.01 at x =100.

The x-axis and y-axis are said to be asymptotes of the function y/x. This means simply that as x gets smaller and smaller, y gets larger and larger without limit. Likewise as x gets larger and larger, y gets smaller and smaller but can never reach the value of zero.

Answer 4

You can start with taking a few points and graphing them. You (obviously) can't use zero or anything less than that, unless you want to get into imaginary numbers. But you can use ¼, 1, 4, etc. Then connect the dots with a nice curved line.

Sound good?

Answer 5

Because x is being raised to a negative power (-1/2), this function is undefined at x=0, and in fact will have a vertical asymptote there.

Plug in a few points, such as (1/4,2), (1,1), (4,1/2) and (100,1/10). Connect them by a smooth curve in such a way that as x approaches 0, your curve approaches the vertical line x=0 (without crossing it!)

Answer 6

the ordered pairs are (1,+/-1);(4,+/-2);(9,+/-3),(16,+/-4);
(25,+/-5);(36,+/-6);(49,+/-7);(64,+/-8);
(81,+/-9);(100,+/-10)
plot these points and join by a smooth curve

Answer 7

If you don't have a graphing calculator, here's a nifty little site that I find really useful:

http://www.coolmath.com/graphit/index.html

It graphs things for you :D