How many revolutions per hour would the earth have to make in order to overcome gravity and toss us off?

Question

I know things are slightly lighter at the equater because of the equatorial bulge and the earth spinning but how is it figured?

To theif. so how many rphs is it? checking my answer.

Answer 1

Currently, the Earth makes one revolution per day, or 0.083 revolutions per hour. This results in a surface velocity of 465.11 m/s at the equator. The Earth's escape velocity is 11186 m/s, which is 24.05 times faster than the current velocity of objects at the equator. Thus, the Earth would need to rotate 24.05 times faster, or 1 revolution per hour, in order to overcome the gravity of objects at the equator. Bear in mind that objects further from the equator will not be moving as fast because they are not as far from the Earth's axis, and the Earth would need to rotate faster to throw them off. Objects located at the geographic North and South Poles cannot be thrown off, no matter how fast the Earth rotates on its axis.

Answer 2

mv^2/R=GMm/R^2
m=mass of person. R = Radius of the earth . M= mass of the earth. G = gravitational constant.
v^2= GM/R or v= sqrt GM/R.
In fact all the water on the earth would evaporate and all the loose particles would be floating. If the earth is not dense enough then it will flatten out like a disk.

Answer 3

What does the earth have to do with tossing off ? Will the earth actually spin fast enough for us to reach orgasm or is this a urban myth?

Answer 4

6.

Answer 5

Then I wouldn't have to do it myself.