area of a triangle
2006-10-21 22:34:18 · 15 answers · asked by msrooj_2000 1 in Science & Mathematics ➔ Mathematics
1/2 X Breadth X Height
2006-10-21 22:36:27 · answer #1 · answered by *azure* 2 · 0⤊ 0⤋
You start with parallel lines. If you draw two transversals that are parallel to each other, then you have a square. You know how to calculate the area of a square/rectangle. Now, if you stretch these transversals between the parallel lines, the area will always be the same as the original square/rectangle provided the transversals remain parallel to each other. So? Well, any triangle is always half the area of one of these squares/rectangles whether they are stretched or not. Thus is follows that a triangle always has half the area of a corresponding square/rectangle that has been formed from it. This is a very neat geometrical proof.
Furthermore, the area formed by a triangle placed between two parallel lines remains the same even if the transversals (not parallel) are stretched. Cool huh?
Finally, since the area of a rectangle/square between parallel lines is base * height, it follows that the area of a triangle must be 1/2 * base * height.
2006-10-22 02:25:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Any triangle is half of the rectangle made of its base and its vertical height. The formula for the area of a triangle is A=1/2 x base x vertical height
2006-10-21 23:20:52 · answer #3 · answered by maggie_at0303 3 · 0⤊ 0⤋
The area S of a triangle is S = ½bh, where b is the length of any side of the triangle (the base) and h (the altitude) is the perpendicular distance between the base and the vertex not on the base
2006-10-21 22:38:05 · answer #4 · answered by Art 2 · 0⤊ 0⤋
Two ways to find the area of the triangle ABC
1. Area = 1/2*base*height
(base is the length of the base BC
and height is the length of the prependicular drawn from the vertex A to the base BC)
2. Area = sq root of {s(s-a)(s-b)(s-c)} where
s = (a+b+c)/2
where a, b and c are lengths of sides AB, BC and CA
respectively
2006-10-21 22:55:24 · answer #5 · answered by grandpa 4 · 0⤊ 0⤋
there are many ways
1. area= 1/2 (base x height)
from trignometry
2.area = 1/2(b x c x sinA)
3.area = 1/2(a x b x sinC)
4.area= 1/2( a x c x sinB) where a,b,c are sides of a triangle & A,B,C are angles of a triangle
5 Hero`s formulae
area = [s(s-a)(s-b)(s-c)]^1/2 s= (a+b+c)/2
well for more email me.
2006-10-21 22:52:41 · answer #6 · answered by geniuswithU 2 · 0⤊ 0⤋
1/2 * base *height
2006-10-22 02:20:01 · answer #7 · answered by neeti 2 · 0⤊ 0⤋
Half the length of the base X perpendicular height.
2006-10-21 22:38:00 · answer #8 · answered by Scabius Fretful 5 · 0⤊ 0⤋
Basic formulae for finding out area is
Area = sq root of {s(s-a)(s-b)(s-c)} where
s = (a+b+c)/2
where a, b and c are the lenghts of sides.
(Works when you know lenghts of all the three sides!!)
One formulae is 1/2xbasexheight. Works when you know Heght and lenght of the base.
If u have more complexity, contact me.
2006-10-21 23:01:52 · answer #9 · answered by Vikram S 2 · 0⤊ 0⤋
1/2 x base x altitude(height)
2006-10-21 22:40:35 · answer #10 · answered by Tan 2 · 0⤊ 0⤋