Let one# be x.Therefore the second # is x+26 .Therefore,according to the problem x+x+26= 64 =>2x=64-26 =>2x=38 =>x=38/2=19. Therefore the first# is 19 and the second # is 19+26=45
2006-10-22 02:13:00
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answer #1
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answered by alpha 7
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Let the number be a
so a + (a+26) = 64
2a + 26 = 64
2a = 64-26
2a = 38
a= 19
the numbers are a = 19, a+16 = 45
we get 19 + 45 = 64
2006-10-22 08:07:59
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answer #2
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answered by Venkatesh V S 5
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Subtract 26 from 64 = 38. 38+26=64 answer- 38
2006-10-22 01:16:53
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answer #3
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answered by Anonymous
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Let x and y be the numbers.
Then x = y+26, and x+y = 64. Therefore y=64-x. Substitute this expression for y into the first equation, and you get
x = (64-x) + 26
or
x = 90 - x.
Move the -x to the left side, and you get
2x=90
so x=45, and y=64-x=19.
2006-10-22 01:16:18
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answer #4
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answered by James L 5
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x is the unknown number
x+26 is the unknown number + 26
64 is the sum of the unknown numbers +26
x + x + 26 = 64
2x + 26=64
2x=38
x=19
19+19+26=64
64=64
2006-10-22 01:29:34
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answer #5
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answered by Yaritza 3
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a - b = 26
a + b = 64
add these together
2a = 90, so a = 45
If a = 45, b = 19
2006-10-22 04:09:23
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answer #6
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answered by maggie_at0303 3
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