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2006-10-21 18:13:53 · 6 answers · asked by Anonymous in Education & Reference Homework Help

6 answers

Let one# be x.Therefore the second # is x+26 .Therefore,according to the problem x+x+26= 64 =>2x=64-26 =>2x=38 =>x=38/2=19. Therefore the first# is 19 and the second # is 19+26=45

2006-10-22 02:13:00 · answer #1 · answered by alpha 7 · 0 0

Let the number be a
so a + (a+26) = 64
2a + 26 = 64
2a = 64-26
2a = 38
a= 19
the numbers are a = 19, a+16 = 45
we get 19 + 45 = 64

2006-10-22 08:07:59 · answer #2 · answered by Venkatesh V S 5 · 0 0

Subtract 26 from 64 = 38. 38+26=64 answer- 38

2006-10-22 01:16:53 · answer #3 · answered by Anonymous · 0 0

Let x and y be the numbers.

Then x = y+26, and x+y = 64. Therefore y=64-x. Substitute this expression for y into the first equation, and you get

x = (64-x) + 26

or

x = 90 - x.

Move the -x to the left side, and you get

2x=90

so x=45, and y=64-x=19.

2006-10-22 01:16:18 · answer #4 · answered by James L 5 · 0 0

x is the unknown number
x+26 is the unknown number + 26
64 is the sum of the unknown numbers +26
x + x + 26 = 64
2x + 26=64
2x=38
x=19
19+19+26=64
64=64

2006-10-22 01:29:34 · answer #5 · answered by Yaritza 3 · 0 0

a - b = 26
a + b = 64

add these together

2a = 90, so a = 45

If a = 45, b = 19

2006-10-22 04:09:23 · answer #6 · answered by maggie_at0303 3 · 0 0

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