solve that if ur smart x^5y^3/x^2+13x+30 multiplication sign x^2+2x-3/x^7y^2?

Question

there solve this.first to solve gets best answer.

Answer 1

nominator x nominator (1)
denominator x denominator (2)

(1) (x^5y^3) * (x^2 + 2x - 3)
factorise x^2 + 2x - 3
in the form of (ax + c)(bx + d) = abx^2 + (ac + bd) x + cd
since ab = 1 then c + d = 2 and cd = -3
so c = 3 and d= -1
(1) will be (x^5y^3)(x+3)(x-1)

(2) (x^2 + 13x + 30)(x^7y^2)
factorise x^2 + 13x + 30 same as above
c+d=13 and cd=30 so c=10 and d = 3
(2) will become (x+10)(x+3)(x^7y^2)

(1)/(2) => (x^5y^3)(x+3)(x-1)
----------------------
(x+10)(x+3)(x^7y^2)
simplifying we get
y(x-1)
-------------
(x+10) x^2

Answer 2

The answer is y(x-1)/ x^2(x+ 10) >Now,the complete solution Given exp.= {(x^5y^3)(x+10)(x+3)}X {(x+3)(x-1)}/x^7y^2 =(x^5y^3/x^7y^2) {(x+3)(x-1)/(x+3)(x+10) =(y/x^2)X (x-1)/(x+10) = y(x-1)/ x^2(x+10) ans.

Answer 3

Okay, I will use basic college algebra with exponential cancelling.

Answer: (x^2y + 2xy - 3y) / (x^4 + 13x^3 + 30x^2)

Answer 4

I can not ansewr that cause you might need the ansewr for school and thats cheating, but te sighn for multiplication is * .

Answer 5

*=multip. sign

Y*(x-1)/(x+10)*X^2

Answer 6

^^^^^^^he's right. That's as far as it will factor.