If y = (0/3)x + 0,
y = 0x + 0
y = 0, which is the equation of the x-axis. It's horizontal.
If all you're looking for is a perpendicular, any vertical line will do... not only x = 0 (the y-axis), but also x = 1, x = 12.8, x = -37, or any x = a (where a is the real number representing the x-intercept).
2006-10-21 12:16:27
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answer #1
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answered by Anonymous
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Try drawing the line
y = 0/3x + 0 for x = 1 to 10
y = 0 divided by 3 + 0 = 0
y = 0 divided by 30 + 0 = 0
Therefore this line is the x axis
Any line perpendicular to it would be parallel to the y axis you can not define this line
2006-10-21 19:10:07
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answer #2
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answered by Philip W 7
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The equation of the line is the same as saying y=0. This is because no matter what x value you put into the equation (except 0) the y value will be zero. So, perpendicular lines to that rule is:
{x: x=R\{0}}. That is, x= any real number, except zero, will be perpendicular to your given equation.
2006-10-21 21:25:03
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answer #3
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answered by Adrian W 2
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the equation simplifies out to y=0 which is a horizontal line. the perpendicular line to a horizontal line is a vertical line which is x=0.
2006-10-21 18:59:01
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answer #4
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answered by Yoni 2
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it is undefined because the perpindicular line to another line has a negative reciprocal slope. 0/3 become 3/0, which is undefined.
2006-10-21 18:56:27
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answer #5
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answered by 120 IQ 4
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there are an infinite ammount of lines perpendicular to that any where from x= -infiniti to X= Infiniti
2006-10-21 18:57:33
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answer #6
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answered by plywoodman 1
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