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-[-2(-3-2) - (-2-3)]

2006-10-21 10:13:32 · 5 answers · asked by shanipooh2004 1 in Education & Reference Homework Help

5 answers

Okay, first you have to distibute the negative symbol throughout the whole thing inside the big brackets. Which gives you 2(-3-2) + (-2-3). The distibute that 2 in front of tha first expression which gives you -6-4 + (-2-3). then take off tha parenthesis from the second expression which gives you -6-4 - 2-3. Then solve it which gives you negative 15.

2006-10-21 16:58:52 · answer #1 · answered by Anonymous · 1 0

-[-2(-3-2) - (-2-3)]
=-[(6+4)+(2+3)]
=-[10+5]
=-15

2006-10-21 18:01:20 · answer #2 · answered by windy288 6 · 0 0

Jm gives the right rule but here is the step by step to show it
-[-2(-3-2) - (-2-3)]
-[-2(-5) - (-5)]
-[10 - (-5)]
-[15]
-15

remember a negative times a negative is a positive

2006-10-21 17:51:57 · answer #3 · answered by anyonexxxxxx9999 4 · 1 0

P arenthesis
E xponents
M ultiplication
D ivision
A ddition
S ubtraction

which is the order in which you are suppoed to do an equation gives you -15

2006-10-21 17:23:08 · answer #4 · answered by Freddie Dearest 2 · 1 0

-[-2(-5) - (-5)]
-[10 + 5]
-15

2006-10-21 18:14:30 · answer #5 · answered by ♥heartbroken♥ 3 · 0 0

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