I need to know the diagonal length of a wardrobe that I am buying as its going in my loft and I need to know that after I have assembled it it will stand up (the diagonal will be taller than the actual height as i move it through an arc to its upright), its a trigonometry thing and Ive forgotten how to do it.
So.... What is the diagonal height if the base is 62cm and the height is 185cm.
The height of the cieling is 197cm.
2006-10-21 07:16:54 · 16 answers · asked by Harret 1 in Science & Mathematics ➔ Mathematics
The previous answer cannot be right, as the diagonal must be greater than the longer side. D = sqrt(62^2 + 185^2) = 195.11, so you will have just under 2 cm to spare.
2006-10-21 07:24:47 · answer #1 · answered by Anonymous · 2⤊ 0⤋
If you want the diagonal height, the Pythagorean theorem works fine, and as several people have pointed out, it's about 195.11 cm.
The thing is, though, if all you're trying to do is move it through your loft, the 195 cm height merely represents the maximum height from corner to corner. You don't need to lift it to its maximum height to move it, though. If you wanted to look at this from a trig aspect, arctan(62/185) â 18.5º... meaning the most you'll need to tilt the wardrobe is that angle to see it reach its maximum height, leaving you less than 2 cm to play with when moving it. By tilting it less than that angle, you'll have more room to lift it.
Either way, you should be able to place it wherever you like in your loft after it's built.
2006-10-21 07:55:54 · answer #2 · answered by Louise 5 · 0⤊ 0⤋
Pythagoras said: a x a + b x b = c x c, where c = diagonal of a right-angled triangle (in this case the diagonal of your wardrobe).
So, 62 x 62 + 185 * 185 = 34225. Therefore square root of this gives you the answer = 195.11 cm (to 2 decimal places).
I wish you luck, but it's mighty close.
2006-10-23 01:01:14 · answer #3 · answered by John L 1 · 0⤊ 0⤋
The correct diagonal height of the wardrobe would be 195.19cm (to two decimal places).
62^2+185^2=x^2
3,844+34,255=38,099
Nick W, I'm afraid your error came from your addition of 3,844+34,255. I'm not sure where your error arose, bh8153, unless you didn't use Windows' excellent built-in calculator.
In either way, the clearance will still be a little under 2cm. (Approximately 3/4")
2006-10-21 07:50:47 · answer #4 · answered by micksmixxx 7 · 1⤊ 0⤋
The maths you need is Pythagoras' theorem; in a right angled triangle the square of the "hypotenuse" (the longest side) is the sum of the squares of the other two sides. So your diagonal is the square root of (62 squared +185 squared) = 195.1cm.
So you're in luck, it will just about fit!
can i have 10 points 4 that!?
2006-10-21 08:18:47 · answer #5 · answered by katie 2 · 0⤊ 0⤋
Are you tryng to say you're going to make the wardrobe stand on it's corner???
Anyway, up to you what you want to do and how but the answer to you question is in fact 195.11cm with the method shown by previous posts.
2006-10-21 15:21:04 · answer #6 · answered by Inviz 2 · 0⤊ 0⤋
using pythagoras theorem
the diagonal=(62^2+185^2)^(1/2)
=195.1127879 cm
since your ceiling is 197cm,your wardrobe
will fit in
i hope that this helps
2006-10-21 20:42:11 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Why not assemble the wardrobe in the loft?
2006-10-22 13:32:30 · answer #8 · answered by mrsjj49 2 · 0⤊ 0⤋
Here's the answer without all the maths jargon...
195.1cm
This guy just wants to know if something will fit in his loft, not a lecture on pythagoras's theorem.
2006-10-21 07:29:49 · answer #9 · answered by Burwell 1 · 2⤊ 2⤋
62^2+185^2=x^2
3844+34255=30381
route of 30381=174.301.
It will fit with room to spare.
2006-10-21 07:19:29 · answer #10 · answered by Nick W 3 · 0⤊ 2⤋