What is the molecular velocity of Hydrogen at 900C?

Answer 1

According to the kinetic theory:

v = sqrt[3kT/m]

"v" is the velocity of the gas molecule. "k" is Boltzmann's constant, which equals 1.3x10^(-23) J/K. "m" is the molecular mass of the molecule.

v = sqrt[3*1173*(1.38 x 10^-23) / 2]

v = 1.6 x 10^(-10) m/s

Answer 2

V^2= 3kT / molecular mass
So, V = (3* 1.380 6505×10−23 J/K*1173K)/2amu (if it is H2))^1/2

V = 1,5586x10^-10 m/s
The 1173K is because K = º C + 273
so, 900 + 273 = 1173 K